<PRE><B>Question 1113307</B>
there are 14 balls in the bag 
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Probability of drawing two red balls = (8/14) * (7/13) = 4/13
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Probability of drawing two blue balls = (6/14) * (5/13) = 15/91
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Probability of drawing 2 red balls and 2 blue balls = (4/13) * (15/91) = 60/1183 
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Note I assume a single ball drawn is not replaced until after the second ball is drawn
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