Question 1113270
<pre>
{{{(2x^2-21x+40)/(4x^2-4x-15)}}}

Factor numerator and denominator:

{{{((2x-5)(x-8))/((2x+3)(2x-5))}}}

As long as 2x-5 does not equal 0
which means x is not 5/2 or 2.5,
then the above equals to

{{{((cross(2x-5))(x-8))/((2x+3)(cross(2x-5)))}}}

or

{{{matrix(1,3,

(x-8)/(2x+3),",",x<>5/2))}}}

Edwin</pre>