Question 1113234
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You did not provide all of the information required to find a definitive solution to this problem.  At a minimum, you would have to provide either the measure of segments AB (or AC) and AD.  Or the measure of any one of the angles of the triangle and the measure of one of the aforementioned segments.


Let *[tex \Large x] represent the measure of either segment AB or AC.  Let *[tex \Large y] represent the measure of segment AD.


Then the measure of segment BD which must be equal to the measure of segment DC is given by *[tex \Large \sqrt{x^2\ -\ y^2}], and the measure of BC is 2 times the measure of BD.


Alternatively, if *[tex \Large y] degrees is the measure of either angle B or angle C (they must be equal), and *[tex \Large x] is the measure of either segment AB or AC, then the measure of BD is *[tex \Large x\cos(y)].  And again, BC is 2 times BD.



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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