Question 1113224
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I have no idea what "2cossec 2A" means, and I'm not sure anyone else in the known universe does either.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \tan A\ +\ \cot A\ =\ \frac{\sin A}{\cos A}\ +\ \frac{\cos A}{\sin A}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ =\ \frac{\sin^2 A\ +\ \cos^2 A}{\sin A\cdot\cos A}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ =\ \frac{1}{\sin A\cdot\cos A}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ =\ \csc A\cdot\sec A]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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