Question 1113136
.
<pre>
In this equation, replace  r = {{{sqrt(x^2 + y^2)}}},  x = {{{r*cos(theta)}}},  y = {{{r*sin(theta)}}}.  Then you will get


r = {{{12/((3x/r) + (4y/r))}}}  ====>  r = {{{(12*r)/(3x + 4y)}}}  ====>  1 = {{{12/(3x + 4y)}}}  ====>  3x + 4y = 12.
</pre>

<U>Answer</U>.  &nbsp;&nbsp;3x + 4y = 12.  &nbsp;&nbsp;Straight line equation.