Question 1112962
the formula for the nth term of an arithmetic sequence is
:
x(n) = a + d(n-1), where a is the first term and d is the common difference
:
x(1) = a + d(1-1) = a, therefore
:
a = 2p +3
:
we see that the second term ( x(2) ) is
:
4p +3 = 2p +3 +d
:
solve for d
:
d = 2p
:
x(3) is
:
5p +2 = 2p +3 +2p(2)
:
solve for p
:
5p +2 = 6p +3
:
*******
p = -1
*******
:
therefore, a=1, d=-2 and the sequence is
:
1, -1, -3
: