Question 1112879
3sec^2 = 2tanx + 4 = 0.


{{{3sec^2(x) = 2tanx + 4 = 0}}}


{{{3(1+tan^2(x))=2tanx +4}}}

{{{3(1+tan^2(x))-2tanx -4=0}}}

{{{3+3tan^2(x)-2tanx -4=0}}}

{{{3tan^2(x)-2tanx -1=0}}}


{{{3tan^2(x)-3tanx+tanx -1=0}}}


{{{3tan(x)(tanx-1)+1(tanx -1)=0}}}

{{{(tanx-1)(3tanx+1)}}}

tanx = 1 or tanx = -1/3