Question 1112844
The formula {{{A = 184*e^(0.038t)}}} models the population of a particular city, in thousands, t years after 1998.
 When will the population of the city reach 302 thousand?
:
{{{184*e^(0.038t) = 302}}} 
divide both sides by 184
{{{e^(0.038t) = 302/184}}}
using natural logs
{{{ln(e^(0.038t)) = ln(302/184)}}}
log equiv of exponent
{{{.038t*ln(e) = ln(302/184)}}}
ln of e is 1
{{{.038t = ln(302/184)}}}
use the calc to find the decimal equiv
.038t = .49549
t = {{{.49549/.038}}}
t ~ 13 yrs, 1998 + 13 = 2011