Question 1112787
Square root of 160^7y^6z^3
sqrt (160) is sqrt(16)*sqrt(10)=4 sqrt (10)
of y^6 is y^3
of z^3 is z^(3/2)=z* sqrt(z)
bring together the radicals and the rationals
4*y^3*z*sqrt(10*z)
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This is sqrt(25*6)+sqrt(9*6)+3*2 sqrt(6)
Or 5 sqrt(6)-3 sqrt(6)+6 sqrt (6)
=8 sqrt (6), since the radical terms are alike.