Question 1112683
Two tail tests have an equal not equal dichotomy. This is one tail.
The null hypothesis has mean of 9 and the sample has mean 10.  The z test will be positive z >1.282
value of test statistic
z=(x-mean)/sigma/sqrt(n)
=(10-9)/2/sqrt(30)=1*sqrt(30)/2=2.74
Reject Ho
p-value is probability z > 2.74, and that is 0.0031.

If this result were by chance, it would occur about 3 times in a 1000. or 0.31% of the time.