<PRE><B>Question 1112582</B>
let x = the first angle.
let y = the second 


second angle is 6 degrees larger than 2 times the first angle.


equation for that is y = 2x + 6


x + y = 90 because the angles are complementary.


replace y with 2x + 6 and you get:



x + 2x + 6 = 90


subtract 6 from both sides and combine like terms to get:


3x = 84


solve for x to get x = 84/3 = 28 degrees.


y = 2x + 6 = 2 * 28 + 6 = 62


28 + 62 = 90 so the angles are complementary


62 = 2 * 28 + 6 = 56 + 6 = 62


all checks out.


first angle is 28 degrees


second angle is 62 degrees.





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