Question 1112539
{{{y=7(1.0164)^x}}}


When y would double
{{{2=1*(1.0164)^x}}}

{{{1.0164^x=2}}}

{{{log((1.0164^x))=log((2))}}}

{{{x=log((2))/log((1.0164))}}}

{{{x=0.30103/0.0070646}}}

{{{42.61}}}

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