Question 1112536
The signal ratio (S) in decibels of am amplifier is modeled by S=10 log (P output/P input).
 If an amplifier gains 13 dB with an input of 9.8 W, what is the output power in W?
{{{10*log((Po)/(9.8))}}} = 13
{{{log((Po)/(9.8))}}} = {{{13/10}}}
{{{log((Po)/(9.8))}}} = 1.3
find the antilog {{{10^x}}} of both sides
{{{(Po)/(9.8)}}} = 19.952
Po = 9.8 * 19.952
Po = 195.5 watts, output power
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Check on a calc
{{{10*log((195.5/9.8))}}} = 12.999 ~ 13 db