Question 1112437
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<pre>
Let "r" be the rate of the slower train, in miles per hour.

Then the rate of the faster train is (r+20) mph.


The distance covered by the slower train in 4 hours is 4r miles.

The distance covered by the faster train in 4 hours is 4*(r+20) miles.

Since the trains move in opposite directions, the distance between them is the sum of the two distances above.

It gives you an equation 

4r + 4*(r+20) = 600.


Simplify and solve for "r":

4r + 4r + 80 = 600

8r = 600 - 80 = 520

r = {{{520/8}}} = 65.


<U>Answer</U>. The rate of the slower train is 65 mph.  The rate of the faster train is 65+20 = 85 mph.
</pre>

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See introductory lessons on Travel and Distance problems

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems-for-two-bodies-moving-toward-each-other.lesson>Travel and Distance problems for two bodies moving in opposite directions</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Travel and Distance problems for two bodies moving in the same direction (catching up)</A>

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