<PRE><B>Question 1112428</B>
 find csc 0 if 0 is an angle in standard position whose terminal side passes through (-12, 5) 
-----
csc = 1/sin = r/y
r = sqrt[12^2+5^2] = sqrt[144+25] = sqrt(169) = 13
====
csc(t) = 13/5
---
Ans: Theta = arcsin(5/13) = 22.62 degrees
------------
Cheers,
Stan H.
-----------</PRE>