Question 1112372
length*width=area
l*(5/3)=55/12 m^2
l=55/12 divided by 5/3 or 55/12*3/5
l=11/4 or 2.75m
half perimeter is the sum of 5/3 and 11/4, with common denominator of 12, it is (20+33)/12=53/12
Full perimeter is twice that or 53/6 m.  This is 8 5/6 meters, which is more than 8 3/4 meters of material, so the answer is no, not enough material.