<PRE><B>Question 1112328</B>
 Find two numbers 
a &amp; b
such that, if 18 is added to the first number, it becomes twice the second number.
a + 18 = 2b
 And if 16 is added to the second number, it becomes three times the first number 
3a = b + 16
rearrange for substitution
b = 3a - 16
replace (3a-16) for b in the 1st equation
a + 18 = 2(3a - 16)
a + 18 = 6a - 32
18 + 32 = 6a - a
50 = 5a
a = 10
:
b = 3(10) - 16
b = 14
:
:
Check in the 1st equation
10 + 18 = 2(14)
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