Question 99894
To find the axis of symmetry, use this formula:


{{{x=-b/(2a)}}}


From the equation {{{y=x^2-3x+2}}} we can see that a=1 and b=-3


{{{x=(--3)/(2*1)}}} Plug in b=-3 and a=1



{{{x=3/(2*1)}}} Negate -3 to get 3



{{{x=(3)/2}}} Multiply 2 and 1 to get 2



So the axis of symmetry is  {{{x=3/2}}}





Notice if you graph the equation {{{y=x^2-3x+2}}} you get

{{{drawing(900,900,-8.5,11.5,-10.25,9.75,
grid( 1 ),
graph(900,900,-8.5,11.5,-10.25,9.75, x^2-3x+2),
circle(1.5,-0.25,0.05),
circle(1.5,-0.25,0.08)
)}}}


and you can see there is a minimum at the axis of symmetry