Question 1112053
Problem Page The area of a rectangle is 65ft^2 and the length of the rectangle is 3ft less than twice the width. Find the dimensions of the rectangle. 
Width = W
Length = 2W-3
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Equation:
W(2W-3) = 65
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2W^2 - 3W - 65 = 0
W = [3+-sqrt(9-4*2*-65)]/4
W = [3+-sqrt(529)]/4
positive solution:
W = 6.5 ft (width)
2W-3 = 10 ft (length)
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Cheers,
Stan H.
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