Question 1112022
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area of a rectangle is 28m^2, and the length of the rectangle is 1m more than twice the width. Find the dimensions 
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If x is the width, then length is 2x+1.


The area was given, and equation from description is {{{x(2x+1)=28}}}.


Look for and try checking the factorizations of 28, if you like, but...


{{{2x^2+x-28=0}}}
Solve this for x, using general solution for quadratic formula.


{{{x=(-1+sqrt(1-4*2*(-28)))/(2*2)}}}

{{{x=(-1+sqrt(1+224))/4}}}

{{{x=(-1+15)/4}}}

{{{x=14/4}}}

{{{x=7/2}}}

{{{highlight(x=3&1/2)}}}----------------USE THIS TO EVALUATE THE LENGTH.