Question 1111910
One doubleing period  {{{45/45}}}.
x minutes, {{{x/45}}};


{{{y=10000(2)^(x/45)}}}


If y=60000, find x.
{{{10000*2^(x/45)=60000}}}

{{{2^(x/45)=6}}}

{{{(x/45)log((2))=log((6))}}}


{{{x=45*log((6))/log((2))}}}, and you can use calculator or table of common logarithms.