Question 1111973
Two cyclists leave towns 240 km apart at the same time and travel toward each other. One cyclist travels 4km/h faster than the other. If they meet in 5 hours, what is the rate of each cyclist?

Distance = 240 km
slow cyclist speed = x
fast cyclist speed = (x+4)
travel toward each

add up speed
= x+x+4  -> 2x+4

t= d/s

5 =240/(2x+4)
5(2x+4)=240
10x+20 =240
10x=220
x=22

Rate of fast cyclist:26 km/h
Rate of slow cyclist:22 km/h