Question 1111938
How far from the base of a vertical cliff 0.8 meters high does a car land if it drove off horizontally at 61 kph?
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Find the time to impact:
h(t) = -4.9t^2 --- t in seconds
-0.8 = -4.9t^2
t^2 = 8/49
t = 2sqrt(2)/7 seconds
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61 km/hr = 61000/3600 m/sec
Horizontal distance = (305/18)*2sqrt(2)/7 meters
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That's some cliff.