Question 1111915
 Two cars race on a 4 mile oval track.
 The sum of their rates is 200 miles per hour.
 Find the rate of each if the faster car gains one lap in 40 minutes.
Let a = the faster car rate
:
In 40 min car a is 4 mi ahead of slower car
therefore, in one hr it will be 6 mi ahead.
Car a is 6 mph faster than the slower car
a + (a-6) = 200
2a = 206
a = 103 mph, slower car = 97 mph