Question 1111892
The frustum has regular hexagon bases. The upper base measures 16 ft. on a side and the lower base measures 29 ft. on a side. The altitude of the frustum is 16 ft.  Find the mass of the frustum, if its density is 99 lbs. per cu. ft.
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Find the volume.
The side length of the hexagon between the bases (8 ft from either) is (29+15)/2 = 22.5 ft
The area is ns^2*cot(180/n)/4 where n = # of sides & s = side length
Area = 6*22.5^2*sqrt(3)/4 = 759.375*sqrt(3) sq ft
Vol = Area*16 = 12150*sqrt(3) cubic ft
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Mass = Vol*density