Question 1111872
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<pre>
Let  x  be the amount invested at 6%  (in dollars).


Then the remainder investment is (15000-x) dollars.


Next, write this equation

<U>interest</U> = <U>interest</U>    (as the condition states !)


0.06x    = 0.04*(15000-x)


0.06x = 0.04*15000 - 0.04x

0.06x + 0.04x = 0.04*15000

0.1x = 0.04*15000  ====>  x = {{{(0.04*15000)/0.1}}} = 6000.


<U>Answer</U>.  $6000 was invested at 6%.  The rest,  15000-6000 = 9000 dollars was invested at 4%.


<U>Check</U>.   0.06*6000 = 360 dollars.

         0.04*9000 = 360 dollars.   ! The same value !  Solved correctly !
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To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.



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In this case, please refer to the problem ID number 1111872.


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