Question 1111752
let R10 be the number of RS 10 notes and R50 be the number of RS 50 notes
:
1) R10 + R50 = 60
:
2) (10 * R10) + (50 * R50) = RS 1000
:
solve equation 1 for R10 and substitute for R10 in equation 2
:
R10 = 60 - R50
:
(10 * (60 - R50) + (50 * R50) = RS 1000
:
600 - 10R50 + 50R50 = 1000
:
40R50 = 400
:
R50 = 10
R10 = 60 - 10 = 50
:
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There are 10 RS 10 notes and 50 RS 50 notes
:
check answer
:
(50 * RS 10) + (10 * RS 50) = RS 1000  
:
500 RS + 500 RS = RS 1000
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