Question 1111683
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Add the measures of the two angles you are given and subtract from *[tex \Large 180^{\circ}] to get the measure of the third angle.  113 + 47 = 160, 180 - 160 = 20


Use the Law of Sines:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{a}{sin(A)}\ =\ \frac{b}{sin(B)}\ =\ \frac{c}{sin(C)}]


Just plug in numbers:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{4.1}{sin(20^{\circ})}\ =\ \frac{b}{sin(47^{\circ})}\ =\ \frac{c}{sin(113^{\circ})}]


The rest is calculator work. Calculate *[tex \Large b] and *[tex \Large c] from the relationship above, then calculate *[tex \Large 3(4.1\ +\ b\ +\ c)\ *\ $14.70]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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