Question 1111535
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P(no head) = P(tails twice) = (0.7)(0.7) = 0.49<br>
P(exactly one head) = P(tails then heads OR heads then tails) = (0.7)(0.3)+(0.3)(0.7) = .21+.21 = .42<br>
P(two heads) = (0.3)(0.3) = 0.09<br>
Note that the probabilities of all possible cases sum to 1, as they must:
0.49+0.42+0.09 = 1.00