Question 1111515
<pre>
a<sub>1</sub> = 1+1 = 2
a<sub>2</sub> = 2²/4 = 1
a<sub>3</sub> = 3+1 = 4
a<sub>4</sub> = 4²/4 = 4
a<sub>5</sub> = 5+1 = 6
a<sub>6</sub> = 6²/4 =9
a<sub>7</sub> = 7+1 = 8

a<sub>n</sub> = [n mod 2](n+1) + [(n+1) mod 2](n²/4) 

Edwin</pre>