<PRE><B>Question 1111480</B>
 What are the length and width of a rectangle of the length exceeds the width by 55 inches and the perimeter is 198 inches? 
2(L+W) = 198
L = W+55
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L+W = 99
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W+55+W  = 99
2W = 44
Width = 22 inches
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Length = W+55 = 77 inches
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Cheers,
Stan H.
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