Question 1111427
a) {{{P=0}}}, none of the balls are colored red and white.
.
.
.
b) {{{P(Y_or_R)=P(Y)+P(R)}}}
Without replacement,
{{{P(Y_or_R)=6/15+5/14=53/70}}}
With replacement,
{{{P(Y_or_R)=6/15+5/15=11/15}}}
.
.
.
c) Find the probability for a red ball,
{{{P(R)=5/15=1/3}}} 
So the answer is the complement,
{{{P=1-1/3}}}
{{{P=2/3}}}
.
.
.
d) Neither red nor yellow means white,
{{{P(W)=4/15}}}