Question 1111209
9x+2y+3x=3  There is a typo assumed 3z
2x-y-2z=4
y-12x-12z+6=0
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9x+2y+3z=3  .......1
2x-y-2z=4..........2
y-12x-12z+6=0......3

9	x	+	2	y	+	3	z	=	3		
2	x	+	-1	y		-2	z	=	4		
											
-12	x	+	1	y	+		-12	z	-6		
											
											
											
consider equation 1 &2				Eliminate y							
Multiply 1 by			1				1				
Multiply 2 by			2				1				
we get											
9	x		+	2	y	+	3	z	=	3	
4	x		+	-2	y	+	-4	z	=	8	
Add the two											
13	x		+	0	y	+	-1	z	=	11	-------------4
consider equation 2 & 3				Eliminate y							
Multiply 2 by				1							
Multiply 3 by				1							
we get											
2	x	+	-1	y	+	-2	z	=	4		
-12	x	+	1	y	+	-12	z	=	-6		
Add the two											
-10	x	+	0	y	+	-14	z	=	-2	-------------5	
Consider (4) & (5)			Eliminate x								
Multiply 4 by				10							
Multiply (5) by				13							
we get				2							
130	x	+	-10	z	=	110					
-130	x	+	-182	z	=	-26					
Add the two											
0	x	+	-192	z	=	84					
/											
z	=	-29		-  7/16							
											
Plug the value of z in						(5)					
-10	x	+	6  1/8 		=	-2					
-10	x	=	-8  1/8 								
x	=	-12	OR	 13/16							
plug value of x & z in					1						
7  5/16	+	2	y	+	-1  5/16	=	3				
2	y	=	3      	+	-7  5/16	+	1  5/16				
	y=	-1.5