<PRE><B>Question 1111383</B>
 Find the maximum slope of the line tangent to the curve y = -x³+6x²+16x+20. 
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Slope at every point = -3x^2+12x+16
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To find max slope take the derivative and solve::
-6x+12 = 0
x = 2
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Ans: Max Slope = -3*2^2+12*2+16 = -12 + 24 + 16 = 28
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Cheers,
Stan H.
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