Question 1111377
 Find the equation of the line which passes through the point (-3,5) and is perpendicular to the line 4x+3y=6. Express your answer in slope-intercept form. 
Find the slope of the given equation.
y = (-4/3)x + 2
slope = -4/3
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Find the slope of a line that is perpendicualar to the given line.
m = (3/4)
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Ans Form:: y = mx + b
Solve for "b" if m = 3/4, x = -3, y = 5.
5 = (3/4)(-3) + b
5 = -9/4 + b
29/4 = b
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Ans:: y = (3/4)x + (29/4)
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Cheers,
Stan H.
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