Question 1111350
Assuming it is  {{{ y = -x^3 + 2x^2 + 4x - 5 }}}


then  {{{ dy/dx = -3x^2 + 4x + 4 }}}
and  {{{ d^2y/dx^2 = -6x + 4 }}}

At x=0, {{{ dy/dx = 4 }}}  —>  y is increasing

At x=0, {{{ d^2y/dx^2  = 4 }}}  —>  the curve is concave up