Question 1111306
{{{y=a(x-2)^2-8}}}------takes care of the vertex


{{{y+8=a(x-2)^2}}}
{{{(y+8)/(x-2)^2=a}}}


{{{a=(-4+8)/(0-2)^2}}}-------the given point helps to evaluate factor, a.

{{{a=4/(2^2)}}}

{{{a=1}}}


{{{highlight(y=(x-2)^2-8)}}}