Question 1111133
*[illustration rectsngle].

Peimeter of rectangle = 2(a+b)

perimeter =x

x=2(a+b)

(a+b) =x/2 .........(1)

perimeter of square = 4c

4c = 90-x
c = (90-x)/4...............(2)

4c=90-x
x=90-4c

and x = 2(a+b) from (1)

90-4c = 2(a+b)

4c = 90-2(a+b)

c= 22.5 -1/2(a+b)

1/2(a+b) >11.25
therefore c <11.25

a,b,c are integers

c <11.25

areas are equal

c^2 = ab

c is an integer
11^2 = a*b
If c = 11 then a,b will be 11
But a,b are sides of rectangle they cannot be equal

if c= 10

c^2=ab
100= a.b
factors of 100 are 20 & 5
so a = 20 and b = 5,c=10
Perimeter is 50 which is greater than 45 ( so it is the longer part)

or
a =25 and b =4 , c=10