Question 14566
Okay, for this question, you need two equations that you would solve with substitution or elimination.
The first equation we can derive from the first sentence. 
{{{4q=n}}}
You can check that that equation is true by giving yourself an example. If you have 2 quarters, then you have 8 nickles. Plug it in. If it works, then it is true. 
Your second equation should look like this.
{{{.05n+.25q=3.6}}}
How did I get that?
A nickel is worth 5 cents, .05 of a dollar. 
A quarter is worth 25 cents, .25 of a dollar.
They both add up to become $3.6
You don't have to have the dollar signs in your equation (unless you teacher states otherwise) because it just makes it messier. 
Then you have your system of equations.
{{{4q=n}}}
{{{.05n+.25q=3.6}}}
I would use substitution because it already has the n isolated
Just plug it in and solve.
{{{.05(4q)+.25q=3.6}}}
Multiply and Solve
{{{.2q+.25q=3.6}}}
{{{.45q=3.6}}}
{{{q=8}}}
Since you now know the number of quarters, you have 4 times as many nickels.
The number of nickels would then be 32
You can check by multiplying. 
8 quarters = $2
32 nickels = $1.60
{{{$2+$1.6=$3.60}}}
Your final answer:
8 quarters and 32 nickels
Hope this helps!