Question 1110957
Use the binomial probability formula
:
Probability (P) ( k successes in n trials ) = nCk * p^k * (1-p)^(n-k), where nCk = n! / (k! * (n-k)!
:
for this problem p = 0.012
:
P ( k > or = 2 in 12 trials) = 1 - P(k = 0) - P(k = 1)
:
P(k = 0) = 0.865133
P(k = 1) = 0.126092
:
P ( k > or = 2 in 12 trials) = 1 -0.865133 -0.126092 = 0.008775
:
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P ( k > or = 2 in 12 trials) = 0.00878
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