Question 1110898
Not sure what is meant for your right-side expression but if this:
{{{log(36,6^(5-x))}}}


then  {{{(5-x)log(36,6)}}}

{{{(5-x)(log(6,6)/log(6,36))}}}

{{{(5-x)(1/log(6,6^2))}}}

{{{(5-x)(1/2)}}}


If that, then your equation would be
{{{3-x=(5-x)/2}}}
and you can continue to solve.