Question 1110901
Assume this is the problem
{{{log(81,(3^(x+2))) = x-1}}}
write it in the exponent form
{{{81^(x-1)}}} = {{{3^(x+2)}}}
81 is equal to 3^4, so we can write it
{{{3^(4(x-1))}}} = {{{3^(x+2)}}}
{{{3^((4x-4))}}} = {{{3^((x+2))}}}
therefore
4x - 4 = x + 2
4x - x = 2 + 4
3x = 6
x = 2