Question 99676
4x^2-12x>0
factor: 4x(x-3)>0
4x>0...x>0
x>3
Test point method find a value of f(x) below 0, between 0 and 3, and above 3:
f(-1)=16
f(1)=-8
f(4)=16
f(x)>0 when x<0 or x>3
the graph tells all.
Ed
{{{graph(500,500,-10,10,-10,10,4x^2-12x)}}}