Question 1110754
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The angle between the hands at that time is {{{(1/6)*360}}} = 60 degrees.


Now apply the cosine law:


c^2 = 6^2 + 4^2 - 2*6*4*cos(60) = 36 + 16 - 2*6*4*(1/2) = 28.


Hence, the distance under the question is  {{{sqrt(28)}}} = 5.29 cm (approximately).
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