<PRE><B>Question 1110715</B>
&lt;br&gt;
To use substitution, you want to solve one of the equations for one of the variables and substitute the expression you get into the other equation.&lt;br&gt;
(1) {{{(-2/3)x+y = 2}}}
(2) {{{ 2x-3y = 6}}}&lt;br&gt;
It looks as if it will be easiest to solve (1) for y:&lt;br&gt;
(1) {{{y = (2/3)x+2}}}&lt;br&gt;
Now replace &quot;y&quot; in (2) with &quot;(2/3)x+2&quot;:&lt;br&gt;
{{{2x-3((2/3)x+2) = 6}}}
{{{2x-2x-6 = 6}}}
{{{-6 = 6}}}&lt;br&gt;
The equation we ended up with is never true; that means the system of equations has no solution.&lt;br&gt;
And in fact the two equations are equations of parallel lines</PRE>