Question 1110678
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<pre>
Let "r" be the slower rate, in km/h.


The condition says

3*(r+5) = {{{(10/3)*r}}}.    (1)


Here 3 is "3 hours",  {{{10/3}}} = {{{3}}}{{{1/3}}} hours = 3 hours and 20 minutes.


From equation (1), 


9*(r+5) = 10r  ====>  9r + 45 = 10r  ====>  r = 45.


The slower rate is 45 km/h.  The faster rate is 5 km/h more:  45 + 5 = 50 km/h.


The distance under the question is 3*50 = 150 kilometers.
</pre>

Solved.


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