Question 1110652
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With only this information, you can't find a single solution.  But you can find a finite set of solutions knowing that the numbers of white and blue envelopes must be whole numbers.<br>
{{{.02w + .035b = 240.50}}}
{{{20w + 35b = 240500}}}
{{{4w + 7b = 48100}}}<br>
In this equation, 4w and 48100 are multiples of 4, so 7b must be a multiple of 4.  Then, since 4 and 7 have no common factor, b must be a multiple of 4.<br>
So b can be any multiple of 4 for which 7b is no more than 48100; and for each of those values of b the value of w is determined.<br>
Note that each time you add 4 to the value of b, the value of w has to decrease by 7 for the sum of 4w and 7b to remain the same.<br>
So to make a complete list of the solutions, you could start with b=0, which gives x=12025; then repeatedly increase b by 4 and decrease w by 7 until the value of w becomes negative.<br>
(b,w) =
(0,12025)
(4,12018)
(8,12011)
(12,12004)
...
etc.