<PRE><B>Question 1110584</B>
P(0 white) = (3/5)(2/4) = 6/20 =  &lt;b&gt; 3/10 &lt;/b&gt;
P(1 white) =  P(white then black) + P(black then white) 
                 =  (2/5)(3/4) + (3/5)(2/4) = 6/20 + 6/20 = 12/20 = &lt;b&gt; 6/10 &lt;/b&gt;
P(2 white) = (2/5)(1/4) = 2/20 = &lt;b&gt; 1/10 &lt;/b&gt;

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Check:
Since one of the above events MUST happen, the sum of their probabilities must be 1:
3/10 + 6/10 + 1/10 = 10/10 = 1   (ok)


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