Question 1110446
36/839 is point estimate probability or 0.0429
99% CI has z of 2.576
the interval width is 2.576* sqrt (p*(1-p))/n
this is 2.576*sqrt (.0429*.9571)/839; sqrt term is 0.0700
the interval width is 0.0180
the interval is (0.025, 0.061)
The best choice of meaning is the second--that 99% of all CIs created this way would include the true mortality rate.  It wouldn't include all confidence intervals.

Yes, both np and nq are greater than 5.