Question 1110285
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Here is a quick mental math way to solve problems like this....<br>
If all 200 tickets were $40 tickets, the total would have been $8000; that is $8000-$6641 = $1359 more than the actual total.<br>
The difference between the two ticket prices is $9, so the number of $31 tickets was 1359/9 = 151.<br>
151 tickets were sold beforehand; 49 were sold at the door.